The bond order of 2 justifies the presence of double bond in O 2 molecule. It has two unpaired electron, therefore it is paramagnetic in nature.Īs bond dissociation energies are directly proportional to the bond order, therefore, the dissociation energies of these molecular species are in the order:Īs bond length is inversely proportional to bond order, therefore, bond length will be in the order: It has one unpaired electron, therefore it is paramagnetic in nature. Presence of no unpaired electron indicates it to be diamagnetic. High value of bond order implies that it should have highest bond dissociation energy. The electronic configuration of N2 is KK (σ(2s)) 2 (σ ∗(2s)) 2 (π(2p x)) 2 (π(2p y)) 2 (σ(2p z)) 2īond order value of 3 means that N 2 contains a triple bond. The double bond in C 2 consist of both Pi bonds because the four electrons are present in the two pi molecular orbitals.
Greater the number of unpaired electrons present in the molecular or ion, greater is its paramagnetic nature.Įlectronic configuration of Homonuclear Diatomic Molecules If the molecules has some unpaired electrons ,it is paramagnetic in nature. If all the electrons in the molecule are paired, it is diamagnetic in nature. Greater the bond order, shorter is the bond length.Ħ) Diamagnetic and paramagnetic nature of the molecules the bond order is negative or zero.ģ) Relative stability of molecule in terms of bond orderįor diatomic molecules ,the stability is directly proportional to the bond order.Ī molecule with the bond order of 3 is more stable than a molecule with bond order of 2 and so on.Ĥ) Nature of bond in terms of bond order :īond order 1 ,2 and 3 mean single ,double and triple bond.īond length is found to be inversely proportional to the bond order. The molecule is unstable if N b < Na i.e. Σ(1s) Na ,the molecule is stable because greater number of bonding orbitals are occupied than antibonding orbital, resulting in a net force of attraction.Ģ) If N b < Na, the molecule is unstable because the antibonding influence is greater than the bonding influence, resulting in net force of repulsion.ģ) If N b = Na ,the molecule is again unstable because influence of electrons in the antibonding molecular orbital is greater than the bond influence of electron in the bonding molecular orbitals.Ģ) Stability of molecules in terms of bond orderīond order is defined as half of the difference between the number of electrons present in the bonding and antibonding orbitals. The first ten molecular orbitals may be arranged in order of energy as follow:
Energy level diagram for Molecular orbitals
0 kommentar(er)
